24+3x^2+2x=5(x-2)(x+2)

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Solution for 24+3x^2+2x=5(x-2)(x+2) equation: 



24+3x^2+2x=5(x-2)(x+2)

We move all terms to the left:

24+3x^2+2x-(5(x-2)(x+2))=0

We use the square of the difference formula

3x^2+x^2+2x+4+24=0

We add all the numbers together, and all the variables

4x^2+2x+28=0

a = 4; b = 2; c = +28;
Δ = b2-4ac
Δ = 22-4·4·28
Δ = -444
Delta is less than zero, so there is no solution for the equation

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